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PUZZLES and PUZZLES GALORE!
- Thread starter WildWest74
- Start date
WildWest74
Could be John Wayne
LOL! There's just one left. Who will win, The Spider or The Ref?!?!
*********COPY EVERYTHING BETWEEN THIS AND THE BOTTOM LINE**********
SIX THE HARD WAY
(0!+ 0!+ 0!)! = 6
(1+ 1+ 1)! = 6
2 + 2 + 2 = 6
3 x 3 - 3 = 6
√4 + √4+ √4 = 6
5 / 5 + 5 = 6
6 + 6 - 6 = 6
7 - 7 / 7 = 6
8 - √(√(8 + 8)) = 6
√9 X √9 - √9 = 6
*******************
SIX THE HARD WAY
(0!+ 0!+ 0!)! = 6
(1+ 1+ 1)! = 6
2 + 2 + 2 = 6
3 x 3 - 3 = 6
√4 + √4+ √4 = 6
5 / 5 + 5 = 6
6 + 6 - 6 = 6
7 - 7 / 7 = 6
8 - √(√(8 + 8)) = 6
√9 X √9 - √9 = 6
*******************
WildWest74
Could be John Wayne
DING DING DING! WE HAVE A WINNAH!
Awesome job, guys!
If you have a puzzle to share, KJ, the floor is yours.
I edited the title so we won't have to limit this to just number puzzles, any brainteaser will do.
Awesome job, guys!
If you have a puzzle to share, KJ, the floor is yours.
I edited the title so we won't have to limit this to just number puzzles, any brainteaser will do.
WildWest74
Could be John Wayne
Thanks, Chad! I needed the factorial hint when I first learned it, but then again my last math class was in 1993, lol!
My last math class was in 2010. Although my wife is currently in school for her master's degree for education with an emphasis on math
OK, Here's a good one that took me a while to figure out. Again, no cheating, and if you've heard the puzzle before, please allow others to solve it.
There is a prison that houses 11 prisoners. The warden has agreed to release all the prisoners if they can solve his puzzle. If they are incorrect, they will be executed.
The prisoners are all kept solitarily, and cannot see or hear any of the other prisoners at any time. There is a room, that has two switches. A and B. Each switch has 2 positions, Up or Down. The switches are not connected to anything. The prisoners will be selected randomly at random intervals and taken into the room. (They could be selected several times in a row, and could be days or years inbetween selections). Once in the room they must flip one, and only one, of the switches. Either one they choose. The initial position of the switches is random and unknown.
The object it to identify when ALL 11 of the prisoners have been to the room, at least once. Any prisoner may answer when they feel confident, but if they are wrong..... execution! They will have 10 minutes to strategize, before it begins. After that, they will be completely cut off from each other again. How will they survive this challenge and be released?
There is a prison that houses 11 prisoners. The warden has agreed to release all the prisoners if they can solve his puzzle. If they are incorrect, they will be executed.
The prisoners are all kept solitarily, and cannot see or hear any of the other prisoners at any time. There is a room, that has two switches. A and B. Each switch has 2 positions, Up or Down. The switches are not connected to anything. The prisoners will be selected randomly at random intervals and taken into the room. (They could be selected several times in a row, and could be days or years inbetween selections). Once in the room they must flip one, and only one, of the switches. Either one they choose. The initial position of the switches is random and unknown.
The object it to identify when ALL 11 of the prisoners have been to the room, at least once. Any prisoner may answer when they feel confident, but if they are wrong..... execution! They will have 10 minutes to strategize, before it begins. After that, they will be completely cut off from each other again. How will they survive this challenge and be released?
WildWest74
Could be John Wayne
OOOOH, this is a good one. I have heard it before, so I will let the rest of the fellas take a crack
Dave in KY
Shave Newbie
I'm with you Dave, I liked math until I graduated in 82 and haven't really used it since inthe realm they're using it. Y'all to smart for me. I need dummer friends. I've heard this one before too and forgot the answer.......back to work for me
GearNoir
“The Disney Princess’s Apprentice”
Work?!
Whats more important, work or helping save the lives of 11 people? Seriously Dave! ?
I feel like I'm missing something. Well, obviously if I haven't figured it out.
Lemmie get this straight. So in theory, once everyone has been in the room at least once, the next person going in should be able to determine they have because of the position of the switches. But the position is random on each person entering, which means the position of the switches shouldn't imply anything. So it's not really about the switches.
Lemmie get this straight. So in theory, once everyone has been in the room at least once, the next person going in should be able to determine they have because of the position of the switches. But the position is random on each person entering, which means the position of the switches shouldn't imply anything. So it's not really about the switches.
WildWest74
Could be John Wayne
Nice to see someone has their priorities straight!!!
It's all about the switches!
Right, so initially they could both be up, both down, or 1 up and 1 down. But the prisoner are the ONLY ones who will be flipping switches. The guards/warden will not interfere after it has started.
WildWest74
Could be John Wayne
This is one of those puzzles that, once you know the answer and think about it for a minute, you feel like it makes perfect sense, but until you get there you just wrack your brain trying to make heads or tails of it. The fact that the prisoners get to come up with a strategy among themselves is critical.
WildWest74
Could be John Wayne
And just a pro tip, puzzles like these are great to use in bar situations, because people will often get so flummoxed that they will gladly buy you a drink for you to give them the answer!